0=4.9t^2-13.63

Solution for 0=4.9t^2-13.63 equation:

0=4.9t^2-13.63

We move all terms to the left:

0-(4.9t^2-13.63)=0

We add all the numbers together, and all the variables

-(4.9t^2-13.63)=0

We get rid of parentheses

-4.9t^2+13.63=0

a = -4.9; b = 0; c = +13.63;
Δ = b2-4ac
Δ = 02-4·(-4.9)·13.63
Δ = 267.148
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{267.148}}{2*-4.9}=\frac{0-\sqrt{267.148}}{-9.8}
=-\frac{\sqrt{}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{267.148}}{2*-4.9}=\frac{0+\sqrt{267.148}}{-9.8}
=\frac{\sqrt{}}{-9.8}
$